If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=5x^2+2x-3
We move all terms to the left:
0-(5x^2+2x-3)=0
We add all the numbers together, and all the variables
-(5x^2+2x-3)=0
We get rid of parentheses
-5x^2-2x+3=0
a = -5; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-5)·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8}{2*-5}=\frac{-6}{-10} =3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8}{2*-5}=\frac{10}{-10} =-1 $
| 7+9+t)=84 | | (x-119)/6=7 | | Y+7x-20=180 | | 6+2x/8=10 | | 35u+18u-5u^2=0 | | d/10+780+d/6=1080 | | x^2*2^31=10000 | | y/92+12=122 | | 1000*1.2^(x)=3000 | | 2x+6=3x-15+6x | | (x-1)=0.5x-0.3 | | y=1/1-0.4y | | 28+4x=72 | | -0.10(15)+0.15x=0.05(x-14) | | 3(2x-3)=2(2x+5)=0 | | C+(c+5)=35 | | 9+5a=36 | | 5(x=4)-(3x=20)=-10 | | 5x-3=17+x | | 5y-6y-3y-5=-15-1 | | X4-10x+12=0 | | F(x)=6+4x+5 | | 4y-3=17-6y | | t=57.662+72.775 | | t=57.662=72.775 | | 32=70/x | | m-17/11=8 | | 4(2c+1)=28 | | 4(2c+1)=38 | | 18=3(2+t | | (x-3)(x=4) | | (x-)(x=4) |